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If \(P(A) = \frac{4}{9}\), \(P(B) = \frac{6}{13}\) and \(P(A \cup B) = \frac{1}{7}\), then find (i) \(P(A \text{ and }B)\) (ii) \(P(\text{neither } A \text{ nor }B)\).
 
Answer:
 
(i) \(P(A \text{ and }B)\) \(=\) ii
 
(ii) \(P(\text{neither } A \text{ nor }B)\) \(=\) ii
 
[Note: Enter the fractional values reduced to their lowest forms.]