31. Five mark exercise problem IV

For a group of \(100\) candidates the mean and standard deviation of their marks were found to be \(60\) and \(15\) respectively. Later on it was found that the scores \(45\) and \(72\) were wrongly entered as \(40\) and \(27\). Find the correct mean and standard deviation.

 

 

Correct mean \(=\)

 

Correct standard deviation \(=\)

 

[Note: Enter the answer rounded to two decimal places.]