Verify the given trigonometric equation — task. Mathematics State Board, Class 10.

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Answer variants:

\sqrt{\frac{36 + \cos θ}{1 - \cos θ} \times \frac{1 - \cos θ}{1 - \cos θ}}

6 (\frac{1}{\sin θ} + \frac{\cos θ}{\sin θ})

6 (\frac{1 + \cos θ}{\sin θ})

\sqrt{\frac{{36 (1 + \cos θ)}^{2}}{\sin^{2} θ}}

\sqrt{\frac{{36 (1 + \cos θ)}^{2}}{1 + \cos^{2} θ}}

\sqrt{\frac{36 (1 + \cos θ)}{1 - \cos θ} \times \frac{1 + \cos θ}{1 + \cos θ}}

\sqrt{\frac{{36 (1 + \cos θ)}^{2}}{1 - \cos^{2} θ}}

Verify that

\sqrt{\frac{36 + 36 \cos θ}{1 - \cos θ}}

\(=\)

6 (cosec θ + \cot θ)

Proof:

LHS \(=\)

\sqrt{\frac{36 + 36 \cos θ}{1 - \cos θ}}

\(=\)

6 (cosec θ + \cot θ)

\(=\) RHS

Did you find an error?

10. Verify the given trigonometric equation