UPSKILL MATH PLUS

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Learn more- Depending on the sides and diagonal lengths, establish an \(ACD\) triangle. Based on \(SSS\) construction.

- Make an arc, which is the length of the other diagonal (with \(D\) as center).

- Make an arc at a specified distance of point \(C\) (third side), on the front arc. Name the two points intersection as \(B\).

- \(A\), \(C\) and \(D\) join \(B\). This completes both diagonals of the quadrilateral \(PQRS\).

Example:

**Construct a**\(GOLD\)

**with quadrilateral measures as follows**.

\(OL = 7.5 cm\), \(GL = 6 cm\), \(GD = 6 cm\), \(LD = 5 cm\), \(OD = 10 cm\).

**Step 1**: Draw Side \(GD = 6 cm\) and cut the \(G\) (\(6 cm\)) and \(D\) (\(5 cm\)) arcs above it. Mark the intersection as \(L\). \(GL\) and \(DL\) are joined.

**Step 2**: Draw and arc from \(L\) equal to \(7.5 cm\) and from \(D\) equal to \(10 cm\), which is the length of \(OL\) and \(OD\) respectively.

**Step 3**:Mark the intersection with \(O\) and \(OG\), \(OL\) and \(OD\) join.

**Thus, the**\(GOLD\)

**is a required quadrilateral**.