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1. Calculate the number of atoms present in \(1\) gram of gold (atomic mass of \(Au=198\)).
  
Data:
 
Given mass of gold \(=1\) \(g\)
 
Atomic mass of \(Au=198\)
 
Avogadro's number \(=6.023\times10^{23}\)
 
Solution:
  
Number of atoms of \(Au\) \(=\) xy
 
Where,
 
x \(=\)
 
y \(=\) 
 
Therefore, the number of atoms present in \(1\) gram of gold \(=\) \(z\times10^{21}\) \(g\)
 
z \(=\)
 
2. Calculate the number of atoms of oxygen and carbon in \(5\) \(moles\) of \(CO_2\).
 
Calculating number of oxygen atoms in \(5\) \(moles\) of \(CO_2\):
  • \(1\)  \(mole\) of \(CO_2\) contains \(2\) \(moles\) of oxygen.
  • \(5\)  \(moles\) of \(CO_2\) contain \(10\) \(moles\) of oxygen.
Solution:
 
Number of atoms of \(O_2\) \(=\)
 
Therefore, the number of atoms of oxygen in \(5\) \(moles\) of \(CO_2=\) \(x\times10^{y}\)
 
  
Calculating the number of carbon atoms in \(5\) \(moles\) of \(CO_2\):
  • \(1\) \(mole\) of \(CO_2\) contains \(1\) \(moles\) of carbon.
  • \(5\) \(moles\) of \(CO_2\) contain \(5\) \(moles\) of carbon.
Number of atoms of \(C\) \(=\)
 
Therefore, the number of atoms of carbon in \(5\) \(moles\) of \(CO_2=\) \(3.011\times10^{y}\)