Multiple choice question I — task. Mathematics State Board, Class 10.

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1. If \(\Delta ABC\) is an isosceles triangle with \(\angle C = 90^\circ\) and \(AC = 5 \ cm\), then \(AB\) is:

$5 \sqrt{2} cm$
$10 \sqrt{2} cm$
$10 cm$
$2.5 cm$

2.

8 (1).png

In the given figure \(\angle BAC = 90^\circ\) and \(AD \perp BC\) then:

\(BD \cdot CD = BC^2\)
\(AB \cdot AC = AD^2\)
\(AB \cdot AC = BC^2\)
\(BD \cdot CD = AD^2\)

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