UPSKILL MATH PLUS

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Learn more**Step 1**: If the given time is \(12\!:\!00\) a.m. (midnight), change \(12\!:\!00\) a.m. as \(00\!:\!00\) hours and proceed further. There is no change up to \(12\!:\!59\) p.m.

**Step 2**: If the given time is \(1\!:\!00\) a. m. to \(12\!:\!59\) p.m., then no time change in \(24\)-hour format. Just write the time as it is in \(4\) digits.

**Step 3**: If the given time is \(1\!:\!00\) p.m. to \(11\!:\!59\) p.m., add \(12\!:\!00\) hours to the given time and write it in \(4\) digits.

Example:

**1**. Convert \(12\!:\!15\) a.m. to \(24\)-hour format.

**Solution**:

By using the above procedure, change \(12\!:\!00\) a.m. as \(00\!:\!00\) hours.

**Therefore**, \(12\!:\!15\) a.m. \(=\) \(00\!:\!15\) hours

**2**. Write \(8\!:\!45\) a.m. in \(24\)-hour format.

**Solution**:

\(8\!:\!45\) a.m. lies between \(1\!:\!00\) a.m. to \(12\!:\!59\) p.m.

By the above procedure, no time change between \(1\!:\!00\) a.m. to \(12\!:\!59\) p.m.

Write the time as it is in \(4\) digits.

**Therefore**, \(8\!:\!45\) a.m. \(=\) \(08\!:\!45\) hours.

**3**. Convert \(8:45\) p.m. in railway format.

**Solution**:

\(8:45\) p.m. lies between \(1:00\) p.m. to \(11:59\) p.m.

Add \(12:00\) hours to the given time by the above procedure.

$\begin{array}{l}\phantom{\rule{0.882em}{0ex}}8:45\\ \underset{\xaf}{+12:00}\\ \underset{\xaf}{\phantom{\rule{0.588em}{0ex}}20:45}\end{array}$

**Therefore**, \(8:45\) p.m. \(=\) \(20:45\) hours.

Important!

**1**. Write hours at the end of the \(24\)-hour time format. Don't write a.m. or p.m. at the end of \(24\)-hour format.

**2**. Minutes will not change in both \(12\)-hour and \(24\)-hour formats.